document.write( "Question 68369This question is from textbook An Incremental Development
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document.write( "Square root of x^2 + 3x - 10 (end square root) + 2 = x \n" );
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Algebra.Com's Answer #48668 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! Please help to solve \n" ); document.write( "Square root of x^2 + 3x - 10 (end square root) + 2 = x \n" ); document.write( ": \n" ); document.write( "Sqrt[x^2 + 3x - 10] + 2 = x \n" ); document.write( ": \n" ); document.write( "Sqrt[x^2 + 3x - 10] = x - 2; subtracted 2 from both sides \n" ); document.write( ": \n" ); document.write( "x^2 + 3x - 10 = (x-2)^2; squared both sides \n" ); document.write( ": \n" ); document.write( "x^2 + 3x - 10 = x^2 - 4x + 4; FOILed (x-2)^2 \n" ); document.write( ": \n" ); document.write( "x^2 - x^2 + 3x + 4x = 4 + 10; combine like terms \n" ); document.write( ": \n" ); document.write( "7x = 14: the x^2's cancel \n" ); document.write( ": \n" ); document.write( "x = 14/7 \n" ); document.write( ": \n" ); document.write( "x = 2 \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "you can check it by substitution in the original equation \n" ); document.write( " \n" ); document.write( " |