document.write( "Question 68369This question is from textbook An Incremental Development
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\n" ); document.write( "\n" ); document.write( "Square root of x^2 + 3x - 10 (end square root) + 2 = x
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Algebra.Com's Answer #48668 by ankor@dixie-net.com(22740)\"\" \"About 
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Please help to solve
\n" ); document.write( "Square root of x^2 + 3x - 10 (end square root) + 2 = x
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\n" ); document.write( "Sqrt[x^2 + 3x - 10] + 2 = x
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\n" ); document.write( "Sqrt[x^2 + 3x - 10] = x - 2; subtracted 2 from both sides
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\n" ); document.write( "x^2 + 3x - 10 = (x-2)^2; squared both sides
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\n" ); document.write( "x^2 + 3x - 10 = x^2 - 4x + 4; FOILed (x-2)^2
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\n" ); document.write( "x^2 - x^2 + 3x + 4x = 4 + 10; combine like terms
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\n" ); document.write( "7x = 14: the x^2's cancel
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\n" ); document.write( "x = 14/7
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\n" ); document.write( "x = 2
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\n" ); document.write( "you can check it by substitution in the original equation
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