document.write( "Question 68357This question is from textbook An Incremental Development
\n" ); document.write( ": please help to solve for c :\r
\n" ); document.write( "\n" ); document.write( "x = p(1/a + m/c)
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Algebra.Com's Answer #48666 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
\"x+=+p%281%2Fa+%2B+m%2Fc%29\"
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\n" ); document.write( "Multiply by p to get rid of the brackets
\n" ); document.write( "\"x+=+p%2Fa+%2B+%28mp%29%2Fc\"
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\n" ); document.write( "Subtract p/a from both sides:
\n" ); document.write( "\"x+-+%28p%2Fa%29+=+%28mp%29%2Fc\"
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\n" ); document.write( "Put the expression on the left over a single denominator:
\n" ); document.write( "\"%28%28ax+-+p%29%29%2Fa+=+%28mp%29%2Fc\"
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\n" ); document.write( "Cross multiply and you have:
\n" ); document.write( "c(ax - p) = a(mp)
\n" ); document.write( ":
\n" ); document.write( "divide both sides by (ax-p)
\n" ); document.write( "c = \"amp%2F%28%28ax-p%29%29\"
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