document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=807976>Question 807976</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A certain number has two digits whose sum is 14. If the digits are reversed, the number will be decreased by 18. Find the number.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #486644 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=486644\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let the digits be x & y x in the ten's place\r<BR>\n" );
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document.write( "x+y=14........................(1)<BR>\n" );
document.write( "10y+x=10x+y-18<BR>\n" );
document.write( "9y-9x=18<BR>\n" );
document.write( "/9<BR>\n" );
document.write( "x-y=2..........................(2)\r<BR>\n" );
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document.write( "add (1) & (2)\r<BR>\n" );
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document.write( "2x=16<BR>\n" );
document.write( "x=8\r<BR>\n" );
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document.write( "x+y=14<BR>\n" );
document.write( "x=8<BR>\n" );
document.write( "so y=6\r<BR>\n" );
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document.write( "the number is 86 </SPAN>\n" );
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