document.write( "Question 807932: The length of a rectangle is 5 cm more than its width. Find the length and width if the area is 104 cm^2.\r
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document.write( "Is this correct?
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document.write( "(x)(x+5x)=104cm^2
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document.write( "x^2+5x=104cm^2
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document.write( "(x^2+5x-104cm^2)= (x^2+5x-104cm)
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document.write( " (x+13)=0(x-5)=0
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document.write( " x=-13 x=5 \n" );
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Algebra.Com's Answer #486627 by Alan3354(69443)![]() ![]() You can put this solution on YOUR website! The length of a rectangle is 5 cm more than its width. Find the length and width if the area is 104 cm^2.\r \n" ); document.write( "\n" ); document.write( "Is this correct? \n" ); document.write( "(x)(x+5x)=104cm^2 \n" ); document.write( "x^2+5x=104cm^2 \n" ); document.write( "(x^2+5x-104cm^2)= (x^2+5x-104cm) \n" ); document.write( " (x+13)=0(x-5)=0 \n" ); document.write( " x=-13 x=5 \n" ); document.write( "-------------------- \n" ); document.write( "13 by 5 --> 65 sq cm, not 104 \n" ); document.write( "============================ \n" ); document.write( "Is this correct? \n" ); document.write( "(x)(x+5x)=104cm^2 ************* It's x*(x+5) = 104 \n" ); document.write( "------------- \n" ); document.write( "Factor 104: \n" ); document.write( "1*104 \n" ); document.write( "2*52 \n" ); document.write( "4*26 \n" ); document.write( "8*13 works. \n" ); document.write( " \n" ); document.write( " |