document.write( "Question 807901: Explain why the equation (x-1)^2 +(x+1)^2 = 0 has no real roots.\r
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Algebra.Com's Answer #486607 by jim_thompson5910(35256)\"\" \"About 
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(x-1)^2 +(x+1)^2 = 0\r
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\n" ); document.write( "\n" ); document.write( "x^2 - 2x + 1 + x^2 + 2x + 1 = 0 ... FOIL/expand\r
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\n" ); document.write( "\n" ); document.write( "2x^2 + 2 = 0 ... Combine like terms.\r
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\n" ); document.write( "\n" ); document.write( "2x^2 = -2 ... Subtract 2 from both sides.\r
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\n" ); document.write( "\n" ); document.write( "x^2 = -2/2 ... Divide both sides by 2.\r
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\n" ); document.write( "\n" ); document.write( "x^2 = -1\r
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\n" ); document.write( "\n" ); document.write( "So at this point, we can see that the equation won't have any real roots. Why? Because solving x^2 = -1 gives us x = i or x = -i, both of which are not real.\r
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\n" ); document.write( "\n" ); document.write( "Note: \"i=sqrt%28-1%29\" which is an imaginary (not real) number
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