document.write( "Question 807873: Prove or disprove the following for all 2x2 matrices A and B\r
\n" ); document.write( "\n" ); document.write( "1) (A + B)^2 = A^2 + 2AB + B^2
\n" ); document.write( "2) A(A+B) = A^2 + AB\r
\n" ); document.write( "\n" ); document.write( "I have a hard time understand proofs and its due next week.
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Algebra.Com's Answer #486601 by jim_thompson5910(35256)\"\" \"About 
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1) (A + B)^2 = A^2 + 2AB + B^2\r
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\n" ); document.write( "\n" ); document.write( "(A + B)^2 = (A+B)(A+B)\r
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\n" ); document.write( "\n" ); document.write( "(A + B)^2 = A(A+B) + B(A+B)\r
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\n" ); document.write( "\n" ); document.write( "(A + B)^2 = A*A+A*B + B*A+B*B\r
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\n" ); document.write( "\n" ); document.write( "(A + B)^2 = A^2+A*B + B*A+B^2\r
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\n" ); document.write( "\n" ); document.write( "This as far as we can go. We CANNOT say that A*B = B*A since matrix multiplication is NOT commutative in general.\r
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\n" ); document.write( "\n" ); document.write( "Therefore (A + B)^2 = A^2 + 2AB + B^2 is false.\r
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\n" ); document.write( "\n" ); document.write( "2) A(A+B) = A^2 + AB \r
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\n" ); document.write( "\n" ); document.write( "A(A+B) = A*A + A*B\r
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\n" ); document.write( "\n" ); document.write( "A(A+B) = A^2 + AB\r
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\n" ); document.write( "\n" ); document.write( "So that confirms A(A+B) = A^2 + AB to be true.
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