document.write( "Question 807881: Why doesn't 256 r^2 + 289 = 0 have a real solution? And why can't it be solved using factorization?\r
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Algebra.Com's Answer #486591 by josmiceli(19441) $\"\"$ $\"About$

You can put this solution on YOUR website!
$\"+256r%5E2+%2B+289+=+0+\"$
\n" ); document.write( "Subtract $\"+289+\"$ from both sides
\n" ); document.write( " $\"+256r%5E2+=+-289+\"$
\n" ); document.write( "Divide both sides by $\"+256+\"$
\n" ); document.write( " $\"+r%5E2+=+-289%2F256+\"$
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\n" ); document.write( " $\"+r+\"$ cannot be a real number because
\n" ); document.write( "there is no real number which, if you
\n" ); document.write( "square it, you get a negative number.
\n" ); document.write( "(+) x (+) = (+)
\n" ); document.write( "and, also
\n" ); document.write( "(-) x (-) = (+)
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\n" ); document.write( "Have you had lessons on imaginary numbers yet?
\n" ); document.write( "That's what you need to solve this
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