document.write( "Question 807886: I am 4 times older than my brother. In 2 years time I will be just 3 times his age. In how many years will my brother be 1/2 my age? \n" ); document.write( "
Algebra.Com's Answer #486588 by josmiceli(19441)\"\" \"About 
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Let \"+m+\" = my age now
\n" ); document.write( "Let \"+b+\" = my brother's age now
\n" ); document.write( "\"+m+%2B+2+\" = my age in 2 years
\n" ); document.write( "\"+b+%2B+2+\" = my brother's age in 2 years
\n" ); document.write( "Let \"+n+\" = the number of years from now
\n" ); document.write( "when my brother will be 1/2 my age
\n" ); document.write( "\"+b+%2B+n+\" = my age in \"+n+\" years
\n" ); document.write( "\"+m+%2B+n+\" = my brother's age in \"+n+\" years
\n" ); document.write( "---------------------------------
\n" ); document.write( "(1) \"+m+=+4b+\"
\n" ); document.write( "(2) \"+m+%2B+2+=+3%2A%28+b+%2B+2+%29+\"
\n" ); document.write( "(3) \"+b+%2B+n+=+%281%2F2%29%2A%28+m+%2B+n+%29+\"
\n" ); document.write( "----------------------------
\n" ); document.write( "This is 3 equations and 3 unknowns, so it's solvable
\n" ); document.write( "Substitute (1) into (2)
\n" ); document.write( "(2) \"+4b+%2B+2+=+3b+%2B+6+\"
\n" ); document.write( "(2) \"+b+=+4+\"
\n" ); document.write( "and, since
\n" ); document.write( "(1) \"+m+=+4b+\"
\n" ); document.write( "(1) \"+m+=+16+\"
\n" ); document.write( "and
\n" ); document.write( "(3) \"+b+%2B+n+=+%281%2F2%29%2A%28+m+%2B+n+%29+\"
\n" ); document.write( "(3) \"+4+%2B+n+=+%281%2F2%29%2A%28+16+%2B+n+%29+\"
\n" ); document.write( "(3) \"+8+%2B+2n+=+16+%2B+n+\"
\n" ); document.write( "(3) \"+n+=+8+\"
\n" ); document.write( "---------------
\n" ); document.write( "In 8 years will my brother be 1/2 my age
\n" ); document.write( "check:
\n" ); document.write( "In 8 yrs I will be \"+16+%2B+8+=+24+\"
\n" ); document.write( "In 8 yrs my brother will be \"+4+%2B+8+=+12+\"
\n" ); document.write( "He is half my age
\n" ); document.write( "OK
\n" ); document.write( "
\n" );