5 to the -3 power\r\n" );
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\r\n" );
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document.write( "Give it a 1 coeffcient\r\n" );
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document.write( "Put it over 1:\r\n" );
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document.write( "
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document.write( "Here are the rules for making negative exponents\r\n" );
document.write( "positive:\r\n" );
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document.write( "1. If a factor of the numerator has a negative\r\n" );
document.write( "exponent, then move the base and exponent\r\n" );
document.write( "from the numerator to the denominator and\r\n" );
document.write( "change the sign of exponent to positive. \r\n" );
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document.write( "2. If a factor of the denominator has a negative\r\n" );
document.write( "exponent, then move the base and exponent\r\n" );
document.write( "from the denominator to the numerator and\r\n" );
document.write( "change the sign of exponent to positive.\r\n" );
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document.write( "You need only the first rule, but remember the\r\n" );
document.write( "second one too for other problems that have\r\n" );
document.write( "negative exponents in the denominator.\r\n" );
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document.write( "So move the
from the numerator to\r\n" );
document.write( "the denominator and change the sign of the -3\r\n" );
document.write( "to +3 So you now have this:\r\n" );
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\r\n" );
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document.write( "And since
=
=
\r\n" );
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document.write( "the final answer is\r\n" );
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document.write( "Edwin
\r
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