document.write( "Question 807106: Factor to find all the zeros x^3-5x^2+16x-30=0 \n" ); document.write( "
Algebra.Com's Answer #486504 by tommyt3rd(5050)\"\" \"About 
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factors of 30:\r
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\n" ); document.write( "\n" ); document.write( "1,2,3,5,15,30\r
\n" ); document.write( "\n" ); document.write( "of which we'd determine that x=3 is a solution such that\r
\n" ); document.write( "\n" ); document.write( "x^3-5x^2+16x-30=(x-3)(x^2-2x+10)=0\r
\n" ); document.write( "\n" ); document.write( "but the quadratic is not factorable over the reals - so we'd need the quadratic formula to determine that x=1+3i, and x=1-3i are the other two factors. Thus the zeros are:
\n" ); document.write( "{3, 1-3i, 1+3i}
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