document.write( "Question 807576: The product and sum of three consecutive terms in a Geometric Progression are 3375 and 65 respectively. Find the difference between the largest and smallest terms of the three numbers \n" ); document.write( "
Algebra.Com's Answer #486389 by stanbon(75887)\"\" \"About 
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The product and sum of three consecutive terms in a Geometric Progression are 3375 and 65 respectively. Find the difference between the largest and smallest terms of the three numbers
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\n" ); document.write( "Product: (a*ar*ar^2) = 3375
\n" ); document.write( "(ar)^3 = 3375
\n" ); document.write( "ar = 15
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\n" ); document.write( "Sum::::: (a + ar + ar^2) = 65
\n" ); document.write( "(a + ar + ar*r) = 65
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\n" ); document.write( "Substitute for ar in the sum to get
\n" ); document.write( "(a + 15 + 15r) = 65
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\n" ); document.write( "Two Equations::
\n" ); document.write( "ar = 15
\n" ); document.write( "a + 15r = 50
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\n" ); document.write( "Substitute for \"a\" and solve for \"r\":
\n" ); document.write( "(50-15r)r = 15
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\n" ); document.write( "15r^2 - 50r + 15 = 0
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\n" ); document.write( "3r^2 - 10r + 3 = 0
\n" ); document.write( "Factor:
\n" ); document.write( "3r^2-9r-r+3 = 0
\n" ); document.write( "3r(r-3)-(r-3) = 0
\n" ); document.write( "(r-3)(3x-1) = 0
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\n" ); document.write( "r = 3 or r = 1/3
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\n" ); document.write( "If r = 3, a = 5 : Then ar^2 = 45:: Then difference = 45-5 = 40
\n" ); document.write( "If r = 1/3, a = 45: Then ar^2 = 5:: Then diffeerence = 5-45 = -40
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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