document.write( "Question 68349: Mr.Thompson invests a principal of $8000; part at 8% per annum and the rest at 10% per annum. After one year, the total interest was $724. How much did Mr. Thompson invest at each rate? \n" ); document.write( "
Algebra.Com's Answer #48636 by checkley71(8403)\"\" \"About 
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.10X+.08(8000-X)=724
\n" ); document.write( ".10X+640-.08X=724
\n" ); document.write( ".02X=724-640
\n" ); document.write( ".02X=84
\n" ); document.write( "X=84/.02
\n" ); document.write( "X=4200 INVESTED @ 10%
\n" ); document.write( "8000-4200=3800 INVESTED @ 8%
\n" ); document.write( "PROOF
\n" ); document.write( "4200*.10+3800*.08=724
\n" ); document.write( "420+304=724
\n" ); document.write( "724=724
\n" ); document.write( "
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