document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=807496>Question 807496</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I want to mix 1liter ofgas at 50 to 1 mixture. How many milliliters of oil do I put in. THANK YOU. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #486330 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=486330\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> I want to mix 1liter ofgas at 50 to 1 mixture. How many milliliters of oil do I put in. <BR>\n" );
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document.write( "1 liter = 1000 ml<BR>\n" );
document.write( "1000/50 = 20 ml<BR>\n" );
document.write( "Add 20 ml of oil --> 1020 ml of mixture<BR>\n" );
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document.write( "If you want 1000 ml of the mixture:<BR>\n" );
document.write( "L = amount of oil<BR>\n" );
document.write( "L + 50L = 1000<BR>\n" );
document.write( "L = 1000/51 =~ 19.6 ml of oil<BR>\n" );
document.write( "980.4 ml of gas<BR>\n" );
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document.write( "Roundoff errors --> 50.02 to 1<BR>\n" );
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document.write( "Using 20 & 980 gives a 49 to 1 mix<BR>\n" );
document.write( "Close enough for any 2-cycle engine<BR>\n" );
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