document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=807456>Question 807456</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How much of an alloy that is 40% copper should be mixed with 300 ounces of an alloy that is 90% copper in order to get an alloy that is 50% copper </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #486313 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=486313\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> ---	percent	----------------	Amount									<BR>\n" );
document.write( "Alloy I	90	----------------			300	ounces						<BR>\n" );
document.write( "Alloy II	40	----------------			x	ounces						<BR>\n" );
document.write( "Mixture	50	----------------	300	+	x	ounces						<BR>\n" );
document.write( "												<BR>\n" );
document.write( "90	*	300	+	40	x	=	50	(	300	+	x	)<BR>\n" );
document.write( "27000	+	40	x	=	15000	+	50	x				<BR>\n" );
document.write( "40	x		-50	x	=	-27000	+	15000				<BR>\n" );
document.write( "-10	x	=	-12000									<BR>\n" );
document.write( "/	-10											<BR>\n" );
document.write( "x	=	1200		ounces	Alloy II							<BR>\n" );
document.write( "												<BR>\n" );
document.write( "m.ananth@hotmail.ca												<BR>\n" );
document.write( "												<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );