document.write( "Question 68356: how can i work this out?\r
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document.write( "The length of a rectangular playing field is 5 ft less than twice its width.
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document.write( "If the perimeter of the playing field is 230 ft, find the length and width of the field. \n" );
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Algebra.Com's Answer #48631 by checkley71(8403)![]() ![]() ![]() You can put this solution on YOUR website! LENGTH=2W-5 & W=WIDTH. THUS \n" ); document.write( "2(2W-5)+2W=230 \n" ); document.write( "4W-10+2W=230 \n" ); document.write( "6W=230+10 \n" ); document.write( "6W=240 \n" ); document.write( "W=240/6 \n" ); document.write( "W=40 ANSWER FOR THE WIDTH \n" ); document.write( "LENGTH=2*24-5 \n" ); document.write( "LENGTH=48-5 \n" ); document.write( "LENGTH=43 \n" ); document.write( "PROOF \n" ); document.write( "2(2*40-5)+2*40=230 \n" ); document.write( "2(80-5)+80=230 \n" ); document.write( "2*75+80=230 \n" ); document.write( "150+80=230 \n" ); document.write( "230=230 \n" ); document.write( " |