document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=8822>Question 8822</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A car travels at 40 km/h for 30 min and 60 km/h for 15 min. How far does it travel in this time? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #4863 by </B><A HREF=/tutors/aboutme.mpl?userid=George><B>George(3)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=George><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=4863\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The equation that describes the distance that car has travelled for specific period of time is: U(t)=S(t)/t,    U(t):speed(km/h) |<BR>\n" );
document.write( "                                   S(t):distance(km)| we firstly convert min  <BR>\n" );
document.write( "                                      t: time(min)  |  to hr<BR>\n" );
document.write( "In our problem, S(t1)=U(t1)*t1<BR>\n" );
document.write( "              =>S(t1)=40*0,5=20km<BR>\n" );
document.write( "                S(t2)=U(t2)*t2<BR>\n" );
document.write( "              =>S(t2)=60*(1/4)=15km<BR>\n" );
document.write( "So the final distance travelled is S=S(t1)+S(t2)=20+15=35km </SPAN>\n" );
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