document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=68364>Question 68364</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/093979862x/algebrahomeworkh>An Incremental Development</A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> PLease help to evaluate : \r<BR>\n" );
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document.write( "x^2 - x^3y - xy if x = -1/2 and y = -1/4 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #48624 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=48624\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> X^2-X^3Y-XY<BR>\n" );
document.write( "(-1/2)^2-(-1/2^3*-1/4)-(-1/2*-1/4)<BR>\n" );
document.write( "1/4-(-1/8*-1/4)-(1/8)<BR>\n" );
document.write( "1/4-(1/32)-1/8<BR>\n" );
document.write( "1/4-1/32-1/8 TO ADD THESE FRACTION YOU NEED TO FIND A COMMON DENOMINATOR <BR>\n" );
document.write( "(32 WORKS BECAUSE 4 & 8 ARE FACTORS OF 32)<BR>\n" );
document.write( "(1*8-1*1-1*4)/32<BR>\n" );
document.write( "(8-1-4)/32<BR>\n" );
document.write( "3/32 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );