document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=807168>Question 807168</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A and B together can do a job in 12 days, and B and C together can do the same job in 16 days. How long would it take them all working together to do the same job if A does 1 1/2 times as much as C? (hint: each pair are doing 1 job)\r<BR>\n" );
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document.write( "Please and thank you </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #486219 by </B><A HREF=/tutors/aboutme.mpl?userid=richwmiller><B>richwmiller(17219)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richwmiller><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richwmiller><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=486219\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 12/a+12/b=1,<BR>\n" );
document.write( "16/b+16/c=1,<BR>\n" );
document.write( "d/a+d/b+d/c=1<BR>\n" );
document.write( "a = 16,   b = 48,   c = 24,   d = 8<BR>\n" );
document.write( "all three do the job in 8 hours.<BR>\n" );
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document.write( "12/16+12/48=1<BR>\n" );
document.write( "3/4+1/4=1\r<BR>\n" );
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document.write( "16/48+16/24=1<BR>\n" );
document.write( "1/3+2/3=1\r<BR>\n" );
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document.write( "8/16+8/48+8/24=1<BR>\n" );
document.write( "1/2+1/6+1/3=1<BR>\n" );
document.write( "ok\r<BR>\n" );
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document.write( " </SPAN>\n" );
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