document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=806357>Question 806357</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The problem I need help with is: log(3x) - log 1.3 = 2.4<BR>\n" );
document.write( "Do I solve as:\r<BR>\n" );
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document.write( "log - 3.9 = 10^2.4\r<BR>\n" );
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document.write( "= 251.1886432<BR>\n" );
document.write( "  ___________  = -64.4073444?<BR>\n" );
document.write( "     -3.9 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #486111 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=486111\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> log(3x) - log 1.3 = 2.4<BR>\n" );
document.write( "log(3x/1.3)=2.4<BR>\n" );
document.write( "convert to exponential form: (base(10) raised to log of number(2.4)=number(3x/1.3))<BR>\n" );
document.write( "2.4^10=3x/1.3<BR>\n" );
document.write( "3x=1.3(2.4^10)<BR>\n" );
document.write( "x&#8776;2747.48 </SPAN>\n" );
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