document.write( "Question 806446: What is...
\n" ); document.write( "Log (4x)=log 2+ log (x-1)
\n" ); document.write( "And please show me the steps and how you arrived to the answer. Thank
\n" ); document.write( "You!!!
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Algebra.Com's Answer #486108 by lwsshak3(11628)\"\" \"About 
You can put this solution on YOUR website!
Log (4x)=log 2+ log (x-1)
\n" ); document.write( "log(4x)=log(2(x-1))
\n" ); document.write( "4x=2(x-1)
\n" ); document.write( "4x=2x-2
\n" ); document.write( "2x=-2
\n" ); document.write( "x=-1
\n" ); document.write( "no solution: 4x and (x-1)>0
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