document.write( "Question 806446: What is...
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document.write( "Log (4x)=log 2+ log (x-1)
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document.write( "And please show me the steps and how you arrived to the answer. Thank
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document.write( "You!!! \n" );
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Algebra.Com's Answer #486108 by lwsshak3(11628)![]() ![]() ![]() You can put this solution on YOUR website! Log (4x)=log 2+ log (x-1) \n" ); document.write( "log(4x)=log(2(x-1)) \n" ); document.write( "4x=2(x-1) \n" ); document.write( "4x=2x-2 \n" ); document.write( "2x=-2 \n" ); document.write( "x=-1 \n" ); document.write( "no solution: 4x and (x-1)>0 \n" ); document.write( " |