document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=806881>Question 806881</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please help me find the eqation and be able to slove for x.<BR>\n" );
document.write( "how many grams of a 50% silver alloy be mixed with a 75% silver alloy to obtain 40 grams of a 60% silver alloy?\r<BR>\n" );
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document.write( "I think it's. ( .5x+.75= ( 40*.6)) but I'm not sure </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #486102 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=486102\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Do it like this one. Only the numbers are different.<BR>\n" );
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document.write( "Amanda wants to make 8 gal. of a 20% saline solution by mixing together a 56% saline solution and a 8% saline solution. How much of each solution must she use?<BR>\n" );
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document.write( "e = amount of 8%<BR>\n" );
document.write( "f = amount of 56%<BR>\n" );
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document.write( "e+ f = 8 (total solution)<BR>\n" );
document.write( "8e + 56f = 20*8 (total saline)<BR>\n" );
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document.write( "e+ f = 8<BR>\n" );
document.write( "e + 7f = 20<BR>\n" );
document.write( "------------ Subtract<BR>\n" );
document.write( "-6f = -12<BR>\n" );
document.write( "f = 2<BR>\n" );
document.write( "e = 6  </SPAN>\n" );
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