document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=806914>Question 806914</A>: <I><SPAN STYLE=\"word-break: break-all;\"> By weight, liquid A makes up 7.0 percent of solution I and 14.5 percent of solution II. If 3 grams of solution I is mixed with 2 grams of solution II, then liquid A accounts for what percent of the weight of the resulting solution? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #486091 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=486091\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> By weight, liquid A makes up 7.0 percent of solution I and 14.5 percent of solution II. <BR>\n" );
document.write( "If 3 grams of solution I is mixed with 2 grams of solution II, then liquid A accounts for what percent of the weight of the resulting solution?<BR>\n" );
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document.write( "Equation::<BR>\n" );
document.write( "liq a + lig a = log a<BR>\n" );
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document.write( "0.7*3 + 0.145*2 = x(3+2)<BR>\n" );
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document.write( "Multiply thru by 1000 to get::<BR>\n" );
document.write( "700*3 + 145*2 = 5000x<BR>\n" );
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document.write( "2100 + 290 = 5000x<BR>\n" );
document.write( "x = 2390/5000<BR>\n" );
document.write( "x = 0.478 = 47.8% (% of liquid A in the mixture)<BR>\n" );
document.write( "------<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( "=========== </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );