document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1375>Question 1375</A>: <I><SPAN STYLE=\"word-break: break-all;\"> obtuse isosolese triangle angles 120/30/30.equal legs 7.what is formula to determine third (longest leg/base)? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #486 by </B><A HREF=/tutors/aboutme.mpl?userid=abhinav75><B>abhinav75(8)</B></A><img src=\"/images/stars/stars-05.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=abhinav75><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=486\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> the median from the central angle would divide the base in two, and would be the altitude as well.  (case of congruent triangles).\r<BR>\n" );
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document.write( "now, the hypotenuse is 7 for the smaller triangle. so, <BR>\n" );
document.write( "cos 30 = sqrt(3)/2 = base/hypotenuse...<BR>\n" );
document.write( "so, base (of the sub triangle) = hypotenuse * cos 30\r<BR>\n" );
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document.write( "so, base of the original triangle = 2 * hypotenuse * cos 30<BR>\n" );
document.write( "= 2*7*sqrt(3)/2<BR>\n" );
document.write( "=7*sqrt(3)<BR>\n" );
document.write( "= 1*1.732<BR>\n" );
document.write( "= 12.124 </SPAN>\n" );
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