document.write( "Question 806668: Find the nonpermissible replacement for the variable in this expression.\r
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document.write( " 5x
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document.write( "6x+3 \n" );
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Algebra.Com's Answer #485987 by jim_thompson5910(35256) ![]() You can put this solution on YOUR website! You CANNOT divide by zero. So 6x+3 cannot be zero. If it were, then...\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "6x+3 = 0\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "6x = -3\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x = -3/6\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x = -1/2\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "So if x = -1/2, then the denominator 6x+3 is 0. This is why x = -1/2 is the value that's not allowed (to avoid division by zero) \n" ); document.write( " |