document.write( "Question 806717: A stone is thrown directly upward from a height of 50 feet with an initial velocity of 56 ft/sec. The height of the stone \"t\" seconds after it has been thrown is given by the formula s(t)=-16t^2+56t+50. Use the appropriate algebraic formula to determine the time at which the ball reaches its maximum height and find what the maximum height is. \n" ); document.write( "
Algebra.Com's Answer #485986 by richwmiller(17219)![]() ![]() You can put this solution on YOUR website! s(t)=-16t^2+56t+50 \n" ); document.write( "parabola \n" ); document.write( "focus | (7/4, 6335/64)=(1.75, 98.9844) \n" ); document.write( "vertex | (7/4, 99)~~(1.75, 99) \n" ); document.write( "semi-axis length | 1/64 = 0.015625 \n" ); document.write( "focal parameter | 1/32 = 0.03125 \n" ); document.write( "eccentricity | 1 \n" ); document.write( "directrix | s = 6337/64 \n" ); document.write( "vertex is the high point \n" ); document.write( "98.9844 ft at 1.75 seconds \n" ); document.write( " \n" ); document.write( " |