document.write( "Question 806717: A stone is thrown directly upward from a height of 50 feet with an initial velocity of 56 ft/sec. The height of the stone \"t\" seconds after it has been thrown is given by the formula s(t)=-16t^2+56t+50. Use the appropriate algebraic formula to determine the time at which the ball reaches its maximum height and find what the maximum height is. \n" ); document.write( "
Algebra.Com's Answer #485986 by richwmiller(17219)\"\" \"About 
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s(t)=-16t^2+56t+50
\n" ); document.write( "parabola
\n" ); document.write( "focus | (7/4, 6335/64)=(1.75, 98.9844)
\n" ); document.write( "vertex | (7/4, 99)~~(1.75, 99)
\n" ); document.write( "semi-axis length | 1/64 = 0.015625
\n" ); document.write( "focal parameter | 1/32 = 0.03125
\n" ); document.write( "eccentricity | 1
\n" ); document.write( "directrix | s = 6337/64
\n" ); document.write( "vertex is the high point
\n" ); document.write( "98.9844 ft at 1.75 seconds
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