document.write( "Question 68312This question is from textbook Geometry
\n" ); document.write( ": Flying Disc. A plastic flyiing disc is circular and has a circular hole in the middle. If the diameter of the outer edge of the ring is 13 inches and the diameter of the inner edge of the ring is 10 inches, what's the area of plastic in the ring? Use 3.14. \n" ); document.write( "
Algebra.Com's Answer #48596 by ptaylor(2198)\"\" \"About 
You can put this solution on YOUR website!
Area of a circle=(pi)r^2=\"%283.14%29%28r%5E2%29\"\r
\n" ); document.write( "\n" ); document.write( "Area of the plastic=area of large disc - area of small disc\r
\n" ); document.write( "\n" ); document.write( "radius of large disc=13/2 inches
\n" ); document.write( "radius of small disc=10/2=5 inches
\n" ); document.write( "Area of large disc=\"3.14%2813%2F2%29%5E2\"\r
\n" ); document.write( "\n" ); document.write( "Area of small disc=\"3.14%285%29%5E2\"\r
\n" ); document.write( "\n" ); document.write( "Area of the plastic=\"3.14%2813%2F2%29%5E2-%283.14%29%285%29%5E2\"\r
\n" ); document.write( "\n" ); document.write( "Area of the plastic=\"3.14%28169%2F4%29-3.14%2825%29\"\r
\n" ); document.write( "\n" ); document.write( "Area of the plastic=\"132.665-78.5\"\r
\n" ); document.write( "\n" ); document.write( "Area of the plastic=\"132.665-78.5=54.165\" sq inches-----------------answer\r
\n" ); document.write( "\n" ); document.write( "Hope this helps---ptaylor\r
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