document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=806580>Question 806580</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The hypotenuse of a right triangle is 1 in longer than the longer leg. The shorter leg measures 7 in less than the longer leg. Find the measure of the longer leg of the triangle. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #485918 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=485918\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> longer leg =x<BR>\n" );
document.write( "shorter leg = x-7<BR>\n" );
document.write( "hypotenuse = x+1\r<BR>\n" );
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document.write( "(x+1)^2= x^2+(x-7)^2\r<BR>\n" );
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document.write( "x^2+2x+1=x^2+x^2-14x+49\r<BR>\n" );
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document.write( "x^2-16x+48=0\r<BR>\n" );
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document.write( "x^2-12x-4x+48=0\r<BR>\n" );
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document.write( "x(x-12)-4(x-12)=0\r<BR>\n" );
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document.write( "(x-12)(x-4)=0\r<BR>\n" );
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document.write( "x=12 Or 4\r<BR>\n" );
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document.write( "longer leg = 12 </SPAN>\n" );
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