document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=67653>Question 67653</A>: <I><SPAN STYLE=\"word-break: break-all;\"> x+5y=28<BR>\n" );
document.write( "-x-2y=-13 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #48591 by </B><A HREF=/tutors/aboutme.mpl?userid=rmromero><B>rmromero(383)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rmromero><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=48591\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x+5y=28<BR>\n" );
document.write( "-x-2y=-13\r<BR>\n" );
document.write( "\n" );
document.write( "Here are the Steps using Substition method<BR>\n" );
document.write( "1. In either equation, solve for one variable in terms of the other.<BR>\n" );
document.write( "2. Substitute for that variable in the other equation. Solve.<BR>\n" );
document.write( "3. Substitute the result from step 2 in either equation. Solve for the other variable.<BR>\n" );
document.write( "4. Check the solution in both original equations.\r<BR>\n" );
document.write( "\n" );
document.write( "Step 1: We are going to choose one equation. Let say x + 5y = 28. We are going to solve x in terms of y ---> x = -5y + 28\r<BR>\n" );
document.write( "\n" );
document.write( "Step 2: Restate the other equation -x - 2y = -13 by subtituting -5y +28 for x and then solve for y.\r<BR>\n" );
document.write( "\n" );
document.write( "-(-5y +28) - 2y = -13    distribute the negative sign to -5y and 28 <BR>\n" );
document.write( "5y - 28 - 2y = -13       combine like terms 5y and -2y<BR>\n" );
document.write( "3y - 28 = -13            add 28 both sides <BR>\n" );
document.write( "3y = 15                  divide both sides by 3<BR>\n" );
document.write( "y = 5\r<BR>\n" );
document.write( "\n" );
document.write( "Step 3: Substitute y = 5 to either equation then solve for x.\r<BR>\n" );
document.write( "\n" );
document.write( "x + 5y = 28 <BR>\n" );
document.write( "x + 5(5) = 28<BR>\n" );
document.write( "x + 25 = 28<BR>\n" );
document.write( "x + 25 - 25= 28 - 25     add -25 both sides<BR>\n" );
document.write( "x = 3\r<BR>\n" );
document.write( "\n" );
document.write( "Step 4 : checking. <BR>\n" );
document.write( "Substitute the result to both equations.<BR>\n" );
document.write( "-x -2y = -13 , x = 3 and y = 5<BR>\n" );
document.write( "-3 -2(5) = -13<BR>\n" );
document.write( "-3 -10 = -13<BR>\n" );
document.write( "-13 = -13   true\r<BR>\n" );
document.write( "\n" );
document.write( "x + 5y = 28 , x= 3 and y = 5<BR>\n" );
document.write( "3 + 5(5) = 28<BR>\n" );
document.write( "3 + 25 = 28<BR>\n" );
document.write( "28 = 28    true\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "so therefore your results are correct x = 3 and y = 5\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "<BR>\n" );
document.write( "<BR>\n" );
document.write( "<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );