document.write( "Question 806577: Stan and Hilda can mow a lawn in 40 minutes if they work together. If Stan takes twice as long to mow the lawn as Hilda when working alone, how long does it take each to move the lawn alone?\r
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document.write( "I'm having a little difficulty with setting this one up. Thank you for any help you can give me. \r
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document.write( "-Laureen Horan \n" );
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Algebra.Com's Answer #485907 by mananth(16946) You can put this solution on YOUR website! Stan and Hilda can mow a lawn in 40 minutes if they work together. If Stan takes twice as long to mow the lawn as Hilda when working alone, how long does it take each to move the lawn alone?\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Let hild take x hours \n" ); document.write( "so she does 1/x of the job in 1 hour\r \n" ); document.write( "\n" ); document.write( "Stan does the job in 2x hours\r \n" ); document.write( "\n" ); document.write( "so he does 1/2x of the job in 1 hour\r \n" ); document.write( "\n" ); document.write( "together they do the job in 40/60 - 2/3 hours\r \n" ); document.write( "\n" ); document.write( "so they do 3/2 of the job in 1 hour\r \n" ); document.write( "\n" ); document.write( "1/x + 1/2x = 3/2\r \n" ); document.write( "\n" ); document.write( "multiply equation by 2x\r \n" ); document.write( "\n" ); document.write( "2+1=3x \n" ); document.write( "3=3x \n" ); document.write( "x=1\r \n" ); document.write( "\n" ); document.write( "Hild can do the job alone in 1 hour\r \n" ); document.write( "\n" ); document.write( "stan in 2 hours \n" ); document.write( " |