document.write( "Question 806427: how do i solve 2log x = log(6-x)? \n" ); document.write( "
Algebra.Com's Answer #485831 by mananth(16946)\"\" \"About 
You can put this solution on YOUR website!
2log x = log(6-x)\r
\n" ); document.write( "\n" ); document.write( "log x^2= log (6-x)\r
\n" ); document.write( "\n" ); document.write( "x^2=6-x\r
\n" ); document.write( "\n" ); document.write( "x^2+x-6=0\r
\n" ); document.write( "\n" ); document.write( "(x+3)(x-2)=0\r
\n" ); document.write( "\n" ); document.write( "x=-3 OR 2
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