document.write( "Question 806116: A rancher wishes to use 86 ft of fencing to enclose a rectangular paddock and subdivide the region into three smaller areas. If the total enclosed area is 225 ft2, find the dimensions of the enclosed region. \n" ); document.write( "
Algebra.Com's Answer #485800 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! A rancher wishes to use 86 ft of fencing to enclose a rectangular paddock and subdivide the region into three smaller areas. \n" ); document.write( " If the total enclosed area is 225 ft2, find the dimensions of the enclosed region. \n" ); document.write( ": \n" ); document.write( "The fence with 4 widths: \n" ); document.write( "2L + 4W = 86 \n" ); document.write( "simplify, divide by 2 \n" ); document.write( "L + 2w = 43 \n" ); document.write( "L = (43-2W) \n" ); document.write( ": \n" ); document.write( "L*W = 225 \n" ); document.write( "Replace L \n" ); document.write( "(43-2w)w = 225 \n" ); document.write( "43w - 2w^2 = 225 \n" ); document.write( "A quadratic equation \n" ); document.write( "-2w^2 + 43w - 225 = 0 \n" ); document.write( "multiply by -1, easier to fator \n" ); document.write( "2w^2 - 43w + 225 = 0 \n" ); document.write( "(2w-25)(w-9) \n" ); document.write( "Two solutions here \n" ); document.write( "2w = 25 \n" ); document.write( "w = 12.5 ft is the width then L = 43-25 = 18 ft is the length \n" ); document.write( "and \n" ); document.write( "w = 9 ft is the width then L = 43-18 = 25 ft is the length \n" ); document.write( " |