document.write( "Question 806116: A rancher wishes to use 86 ft of fencing to enclose a rectangular paddock and subdivide the region into three smaller areas. If the total enclosed area is 225 ft2, find the dimensions of the enclosed region. \n" ); document.write( "
Algebra.Com's Answer #485800 by ankor@dixie-net.com(22740)\"\" \"About 
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A rancher wishes to use 86 ft of fencing to enclose a rectangular paddock and subdivide the region into three smaller areas.
\n" ); document.write( " If the total enclosed area is 225 ft2, find the dimensions of the enclosed region.
\n" ); document.write( ":
\n" ); document.write( "The fence with 4 widths:
\n" ); document.write( "2L + 4W = 86
\n" ); document.write( "simplify, divide by 2
\n" ); document.write( "L + 2w = 43
\n" ); document.write( "L = (43-2W)
\n" ); document.write( ":
\n" ); document.write( "L*W = 225
\n" ); document.write( "Replace L
\n" ); document.write( "(43-2w)w = 225
\n" ); document.write( "43w - 2w^2 = 225
\n" ); document.write( "A quadratic equation
\n" ); document.write( "-2w^2 + 43w - 225 = 0
\n" ); document.write( "multiply by -1, easier to fator
\n" ); document.write( "2w^2 - 43w + 225 = 0
\n" ); document.write( "(2w-25)(w-9)
\n" ); document.write( "Two solutions here
\n" ); document.write( "2w = 25
\n" ); document.write( "w = 12.5 ft is the width then L = 43-25 = 18 ft is the length
\n" ); document.write( "and
\n" ); document.write( "w = 9 ft is the width then L = 43-18 = 25 ft is the length
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