document.write( "Question 806302: I have a bunch of practice workbook questions that I'm struggling with. Here is another one. If somebody could please explain the answer and how you got to the answer. \r
\n" ); document.write( "\n" ); document.write( "The area of a rectangle is 33m sq., and the length of the rectangle is 5m less than twice the width. Find the dimensions of the rectangle.
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Algebra.Com's Answer #485784 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
Given:
\n" ); document.write( "\"+A+=+33+\" m2
\n" ); document.write( "\"+L+=+2W+-5+\" m
\n" ); document.write( "-----------------
\n" ); document.write( "The formula for area is
\n" ); document.write( "\"+A+=+L%2AW+\"
\n" ); document.write( "By substitution:
\n" ); document.write( "\"+A+=+%28+2W+-+5+%29%2AW+\"
\n" ); document.write( "\"+33+=+2W%5E2+-+5W+\"
\n" ); document.write( "\"+2W%5E2+-+5W+-+33+=+0+\"
\n" ); document.write( "Using the quadratic formula:
\n" ); document.write( "\"+W++=+%28-b+%2B-+sqrt%28+b%5E2+-+4%2Aa%2Ac+%29%29+%2F+%282%2Aa%29+\"
\n" ); document.write( "\"+a+=+2+\"
\n" ); document.write( "\"+b+=+-5+\"
\n" ); document.write( "\"+c+=+-33+\"
\n" ); document.write( "\"+W++=+%28-%28-5%29+%2B-+sqrt%28+%28-5%29%5E2+-+4%2A2%2A%28-33%29+%29%29+%2F+%282%2A2%29+\"
\n" ); document.write( "\"+W++=+%28+5+%2B-+sqrt%28+25+%2B+264+%29%29+%2F+4+\"
\n" ); document.write( "\"+W++=+%28+5+%2B-+sqrt%28+289+%29%29+%2F+4+\" ( I can't use the negative square root )
\n" ); document.write( "\"+W+=+%28+5+%2B+17+%29+%2F+4+\"
\n" ); document.write( "\"+W+=+22%2F4+\"
\n" ); document.write( "\"+W+=+11%2F2+\"
\n" ); document.write( "and, since
\n" ); document.write( "\"+L+=+2W+-5+\"
\n" ); document.write( "\"+L+=+2%2A%2811%2F2%29+-5+\"
\n" ); document.write( "\"+L+=+11+-+5+\"
\n" ); document.write( "\"+L+=+6+\"
\n" ); document.write( "The rectangle is 6 m x 5.5 m
\n" ); document.write( "check:
\n" ); document.write( "\"+A+=+L%2AW+\"
\n" ); document.write( "\"+A+=+6%2A5.5+\"
\n" ); document.write( "\"+33+=+33+\"
\n" ); document.write( "OK
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