document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=806163>Question 806163</A>: <I><SPAN STYLE=\"word-break: break-all;\"> In &#916;ABC, X and Y are points on sides AB and BC respectively such that XY parallel to AC and XY divides triangular region ABC into two parts equal in area. Then AX/AB is equal to </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #485717 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=485717\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Intriangle;ABC, X and Y are points on sides AB and BC respectively such that XY parallel to AC and XY divides triangular region ABC into two parts equal in area. Then AX/AB is equal to\r<BR>\n" );
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document.write( "In triangle AXY & ABC\r<BR>\n" );
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document.write( "Angle AXY is congruent to ABC ( corresponding angles)<BR>\n" );
document.write( "Angle A is common\r<BR>\n" );
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document.write( "By AA test of similarity the triangles <BR>\n" );
document.write( "triangle ABC & AXY are similar\r<BR>\n" );
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document.write( "Area of Triangle AXY/area of ABC = AX^2/AB^2\r<BR>\n" );
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document.write( "But The ratio of areas = 1/2\r<BR>\n" );
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document.write( "1/2 = AX^2/AB^2\r<BR>\n" );
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document.write( "1/sqrt(2)= AX/AB\r<BR>\n" );
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