document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=806099>Question 806099</A>: <I><SPAN STYLE=\"word-break: break-all;\"> please help me to solve ihis question: a 5m wide lawn is cultivated all along ihe outside of rectangular plot measuring 80m*40m. what is the total area of the lawn?<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #485700 by </B><A HREF=/tutors/aboutme.mpl?userid=panelboxboy><B>panelboxboy(1)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=panelboxboy><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=485700\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> So P=2l+2w<BR>\n" );
document.write( "P=2(80) + 2(40)<BR>\n" );
document.write( "=160+80<BR>\n" );
document.write( "=240<BR>\n" );
document.write( "So to get the area.. \r<BR>\n" );
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document.write( "240(5)<BR>\n" );
document.write( "=1200 sq. meters\r<BR>\n" );
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