document.write( "Question 68251: I need help to some questions and I need help badly can anyone help me please the questions are as followed:if a=0.65 and b=1.28 and c=-5over2 evaluate - a(-b)+c but the answer I get out of it is three different ones every time its between -4.43,-1.87,and -0.57 I'm confused.The next one is solve the equation for q:6+[Q-2]=-1.The next one is if p=0.75 and q=-1.6,evaluate:p+q-(-0.7).And the last one is solve the equation for b:3over5=9over10b.Thank you for whoever can help thanks \n" ); document.write( "
Algebra.Com's Answer #48570 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! need help to some questions and I need help badly can anyone help me please the questions are as followed: \n" ); document.write( ": \n" ); document.write( "if a=0.65 and b=1.28 and c=-5 over 2 evaluate - a(-b)+c \n" ); document.write( "Since the answer is in decimals change -5/2 to -2.5 (c) \n" ); document.write( ": \n" ); document.write( "-0.65(-1.28) + (-2.5) \n" ); document.write( ": \n" ); document.write( "+.832 - 2.5; minus times a minus is a plus, plus a minus is a minus \n" ); document.write( ": \n" ); document.write( "-1.668 \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( " solve the equation for q: \n" ); document.write( "6 + [Q-2] = -1 \n" ); document.write( ": \n" ); document.write( "Get rid of the brackets: \n" ); document.write( "6 + Q - 2 = -1 \n" ); document.write( ": \n" ); document.write( "Q + 4 = -1; did the math on the left \n" ); document.write( ": \n" ); document.write( "Subtract 4 from both sides: \n" ); document.write( "Q = - 1 - 4 \n" ); document.write( ": \n" ); document.write( "Q = -5 \n" ); document.write( ": \n" ); document.write( "you can check that in the original equation: \n" ); document.write( "6 + [Q-2] = -1 \n" ); document.write( "6 + [-5-2] = -1 \n" ); document.write( "6 + (-7) = -1 \n" ); document.write( "6 - 7 = -1 \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "if p=0.75 and q=-1.6, evaluate: \n" ); document.write( "p + q -(-0.7) \n" ); document.write( ": \n" ); document.write( "Remember a minus a minus is a plus, remove the brackets and you have: \n" ); document.write( "p + q + 0.7 \n" ); document.write( ": \n" ); document.write( "Substitute for p & q \n" ); document.write( ".75 + (-1.6) + .7 \n" ); document.write( ": \n" ); document.write( ".75 - 1.6 + .7 = -.15 \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "solve the equation for b: 3 over 5= 9 over 10b \n" ); document.write( " \n" ); document.write( ": \n" ); document.write( "We want to get rid of the denominators, mult both sides by 10b \n" ); document.write( " \n" ); document.write( ": \n" ); document.write( "After canceling we have: \n" ); document.write( "2b(3) = 9 \n" ); document.write( ": \n" ); document.write( "6b = 9 \n" ); document.write( ": \n" ); document.write( "b = 9/6 \n" ); document.write( ": \n" ); document.write( "b = 3/2 or 1.5 \n" ); document.write( ": \n" ); document.write( "Check, substitute 1.5 for b: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( ": \n" ); document.write( "Hope this helps! \n" ); document.write( ": \n" ); document.write( " |