document.write( "Question 806037: Car travels 200 miles. A second car, making the same trip, travels 10 mph faster than the first car and makes the trip in 1 hour less. Find the speed of each car. ??\r
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Algebra.Com's Answer #485693 by mananth(16946)\"\" \"About 
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First car ------------ speed ---------------x mph-----------200 miles\r
\n" ); document.write( "\n" ); document.write( "time first car = 200/x\r
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\n" ); document.write( "\n" ); document.write( "Second car-----------speed ---------------(x+10) mph----------200 miles\r
\n" ); document.write( "\n" ); document.write( "time second car = 200/(x+10)\r
\n" ); document.write( "\n" ); document.write( "Time first car - time second car = 1\r
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\n" ); document.write( "\n" ); document.write( "\"200%2Fx+-+200%2F%28x%2B10%29+=1\"\r
\n" ); document.write( "\n" ); document.write( "LCD = x(x+10)
\n" ); document.write( "200(x+10)-200x=1*x(x+10)\r
\n" ); document.write( "\n" ); document.write( "200x+2000-200x=x^2+10x\r
\n" ); document.write( "\n" ); document.write( "x^2+10x-2000=0\r
\n" ); document.write( "\n" ); document.write( "x^2+50x-40x-2000=0\r
\n" ); document.write( "\n" ); document.write( "x(x+50)-40(x+50)=0\r
\n" ); document.write( "\n" ); document.write( "(x+50)(x-40)=0\r
\n" ); document.write( "\n" ); document.write( "x= 40 OR -50\r
\n" ); document.write( "\n" ); document.write( "ignore negative\r
\n" ); document.write( "\n" ); document.write( "x= 40 speed of first car\r
\n" ); document.write( "\n" ); document.write( "speed of second car = 40+10 = 50 mph\r
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