document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=68280>Question 68280</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Here is a question:<BR>\n" );
document.write( "At an Italian restaurant there is a jug of heterogeneous oils that are composed of 20 liters of 93% oil type and 10 liters of pure neutral liquid.<BR>\n" );
document.write( "Now, the 93% oils are on the bottom while the neutral liquid is less dense. How much of the oils must I take out of the bottom, so that when I shake the jug up, I get a heterogeneous solution of 64%? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #48569 by </B><A HREF=/tutors/aboutme.mpl?userid=Nate><B>Nate(3500)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Nate><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=48569\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> First, let us find the solution's percentage of oil content:<BR>\n" );
document.write( "(20(93%) + 10(0%))/(30) = ?<BR>\n" );
document.write( "(20(0.93) + 10(0.00))/30 = ?<BR>\n" );
document.write( "18.6/30 = 0.62 or 62%<BR>\n" );
document.write( "On the contrary, you would have to add oils to get a solution of 64% ....<BR>\n" );
document.write( "(18.6 + x(0.93))/(30 + x) = 0.64<BR>\n" );
document.write( "18.6 + 0.93x = 19.2 + 0.64x<BR>\n" );
document.write( "0.29x = 0.6<BR>\n" );
document.write( "x = about 2.1 liters of 93% oils must be added </SPAN>\n" );
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