document.write( "Question 806109: Twice the sum of a number and 3 times a second numbers is 4. The difference of ten times the second number and five times the first is 90. Find the numbers. \n" ); document.write( "
Algebra.Com's Answer #485672 by mananth(16946) You can put this solution on YOUR website! Twice the sum of a number and 3 times a second numbers is 4. The difference of ten times the second number and five times the first is 90. Find the numbers.\r \n" ); document.write( "\n" ); document.write( "one number -----------x \n" ); document.write( "second number---y\r \n" ); document.write( "\n" ); document.write( "2(x+3y)=4 \n" ); document.write( "/2 \n" ); document.write( "x+3y=2 \n" ); document.write( "10y-5x=90\r \n" ); document.write( "\n" ); document.write( "1 x + 3 y = 2 .............1 \n" ); document.write( "Total value \n" ); document.write( "-5 x + 10 y = 90 .............2 \n" ); document.write( "Eliminate y \n" ); document.write( "multiply (1)by -10 \n" ); document.write( "Multiply (2) by 3 \n" ); document.write( "-10 x -30 y = -20 \n" ); document.write( "-15 x + 30 y = 270 \n" ); document.write( "Add the two equations \n" ); document.write( "-25 x = 250 \n" ); document.write( "/ -25 \n" ); document.write( "x = -10 \n" ); document.write( "plug value of x in (1) \n" ); document.write( "1 x + 3 y = 2 \n" ); document.write( "-10 + 3 y = 2 \n" ); document.write( " 3 y = 2 + 10 \n" ); document.write( " 3 y = 12 \n" ); document.write( " y = 4 \n" ); document.write( "x=-10,y=4 \n" ); document.write( " |