document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=806080>Question 806080</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I know the answer to this problem, however I do not understand how to complete each step, only the 1st one, by putting the entire problem under a 1 by using definition of negative exponent.\r<BR>\n" );
document.write( "\n" );
document.write( "(2a to power of -2 times b to the power of 2 times z to the -10th power) all to the -5th power.\r<BR>\n" );
document.write( "\n" );
document.write( "Thanks you, Melissa  (sorry I don't have the fancy symbols) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #485656 by </B><A HREF=/tutors/aboutme.mpl?userid=josmiceli><B>josmiceli(19441)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=josmiceli><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=josmiceli><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=485656\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let's see if I follow you.<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+%28+1+%2F+%28+%282a%29%5E-2+%2A+b%5E2+%2A+z%5E%28-10%29+%29+%29%5E%28-5%29+ ALIGN=MIDDLE  ALT=\"+%28+1+%2F+%28+%282a%29%5E-2+%2A+b%5E2+%2A+z%5E%28-10%29+%29+%29%5E%28-5%29+\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "Hope I got it<BR>\n" );
document.write( "A good way to look at this <BR>\n" );
document.write( "is that it is the same as<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+%28%281+%2F++%282a%29%5E-2%29+%2A+%281+%2F+b%5E2%29+%2A+%281+%2F+z%5E%28-10%29+%29%29%5E%28-5%29+ ALIGN=MIDDLE   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "Now I can use the fact that<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+%28+a%2Ab%2Ac+%29%5Ed+=+a%5Ed+%2A+b%5Ed+%2A+c%5Ed+ ALIGN=MIDDLE  ALT=\"+%28+a%2Ab%2Ac+%29%5Ed+=+a%5Ed+%2A+b%5Ed+%2A+c%5Ed+\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+%281+%2F++%282a%29%5E-2%29%5E%28-5%29+%2A+%281+%2F+b%5E2%29%5E%28-5%29+%2A+%281+%2F+z%5E%28-10%29+%29%5E%28-5%29+ ALIGN=MIDDLE   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "Now reverse the signs of the inner exponents and <BR>\n" );
document.write( "bring them up to the top<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+%28%282a%29%5E2%29%5E%28-5%29+%2A+%28+b%5E%28-2%29%29%5E%28-5%29+%2A+%28+z%5E10+%29%5E%28-5%29+ ALIGN=MIDDLE   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "Now use the fact that<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+%28+a%5Eb+%29%5Ec+=+a%5E%28b%2Ac%29+ ALIGN=MIDDLE  ALT=\"+%28+a%5Eb+%29%5Ec+=+a%5E%28b%2Ac%29+\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+%282a%29%5E%28-10%29+%2A+b%5E%2810%29+%2A+z%5E%28-50%29+ ALIGN=MIDDLE  ALT=\"+%282a%29%5E%28-10%29+%2A+b%5E%2810%29+%2A+z%5E%28-50%29+\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "That's it\r<BR>\n" );
document.write( "\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );