document.write( "Question 805946: A bus company has 4000 passengers daily, each paying a fare of $2. For each $0.15 increase, the company estimates that it will lose 40 passengers per day.
\n" ); document.write( "If the company needs to take in $10450 per day to stay in business, what fare should be charged? \n" ); document.write( "
Algebra.Com's Answer #485638 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
A bus company has 4000 passengers daily, each paying a fare of $2. For each $0.15 increase, the company estimates that it will lose 40 passengers per day.
\n" ); document.write( " If the company needs to take in $10450 per day to stay in business, what fare should be charged?
\n" ); document.write( ":
\n" ); document.write( "let x = no. of .15 increases and no. of 40 passenger losses
\n" ); document.write( ":
\n" ); document.write( "Write a revenue equation
\n" ); document.write( ":
\n" ); document.write( "No. of pass * fare amt = $10450
\n" ); document.write( "(4000-40x)*(2+.15x) = 10450
\n" ); document.write( "FOIL
\n" ); document.write( "8000 + 600x - 80x - 6x^2 = 10450
\n" ); document.write( "Arrange as a quadratic equation
\n" ); document.write( "-6x^2 + 520x + 8000 - 10450 = 0
\n" ); document.write( "-6x^2 + 520x - 2450 = 0
\n" ); document.write( "Simplify divide by -2
\n" ); document.write( "3x^2 - 260x + 1225 = 0
\n" ); document.write( "We can use the quadratic equation here, but this will factor to
\n" ); document.write( "(3x-245)(x-5) = 0
\n" ); document.write( "only one solution is reasonable
\n" ); document.write( "x = 5 fare increase of 15 cents
\n" ); document.write( "2 + 5(.15) = $2.75 fare to take in $10450
\n" ); document.write( ":
\n" ); document.write( "This would reduce the passengers to:
\n" ); document.write( "4000 - 5(40) = 3800 passengers
\n" ); document.write( ":
\n" ); document.write( "3800 * 2.75 = 10450, confirms out solution of x=5 ea 15 cent fare increases \n" ); document.write( "
\n" );