document.write( "Question 806014: A commercial jet took off from Kansas City for San Francisco, a distance of 2550 km, at a speed of 800 km/h. At the same time a private jet, traveling at 900 km/h, left San Francisco for Kansas City. How long after takeoff will the jets pass each other? \n" ); document.write( "
Algebra.Com's Answer #485621 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
A commercial jet took off from Kansas City for San Francisco, a distance of 2550 km, at a speed of 800 km/h. At the same time a private jet, traveling at 900 km/h, left San Francisco for Kansas City. How long after takeoff will the jets pass each other?
\n" ); document.write( "-----------
\n" ); document.write( "KC to SF DATA:
\n" ); document.write( "rate = 800 km/h ; time = t hrs ; distance = 800t km
\n" ); document.write( "--------
\n" ); document.write( "SF to KC DATA:
\n" ); document.write( "rate = 900 km/h ; time = t hrs; distance = 900 km
\n" ); document.write( "-------
\n" ); document.write( "Equation::
\n" ); document.write( "dist + dist = 2550 km
\n" ); document.write( "800t + 900t = 2550
\n" ); document.write( "1700t = 2550
\n" ); document.write( "-----
\n" ); document.write( "t = 1.5 hrs (time till they meet)
\n" ); document.write( "-----------------------
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
\n" ); document.write( "------------
\n" ); document.write( "--- \n" ); document.write( "
\n" );