document.write( "Question 68268This question is from textbook An Incremental Development
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document.write( ":  The sum of the digits of a two-digit counting number was 9. When the digits were reversed, the new number was 45 less than the original number. What was the original number? \n" );
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| Algebra.Com's Answer #48561 by Nate(3500)      You can put this solution on YOUR website! Two Digit Number: 10a + b \n" ); document.write( "a + b = 9 or a = 9 - b \n" ); document.write( "10b + a = 10a + b - 45 \n" ); document.write( "Plug: \n" ); document.write( "10b + 9 - b = 10(9 - b) + b - 45 \n" ); document.write( "9b + 9 = 90 - 10b + b - 45 \n" ); document.write( "9b + 9 = 45 - 9b \n" ); document.write( "18b = 36 \n" ); document.write( "b = 2 \n" ); document.write( "a = 7 \n" ); document.write( "Number: 72 \n" ); document.write( " |