document.write( "Question 805895: The length of a rectangle is 5 times its width. When the length is decreased by 3m and the width is increased by 2m, the area of the new rectangle is 60m squared. find the original length and width. \n" ); document.write( "
Algebra.Com's Answer #485582 by ankor@dixie-net.com(22740)\"\" \"About 
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The length of a rectangle is 5 times its width.
\n" ); document.write( "L = 5w
\n" ); document.write( " When the length is decreased by 3m and the width is increased by 2m, the area of the new rectangle is 60m squared.
\n" ); document.write( "(L-3)*(w+2) = 60
\n" ); document.write( "Replace L with 5w
\n" ); document.write( "(5w-3)(w+2) = 60
\n" ); document.write( "FOIL
\n" ); document.write( "5w^2 + 10w - 3w - 6 = 60
\n" ); document.write( "5w^2 + 7w - 66 = 0
\n" ); document.write( "Factors to
\n" ); document.write( "(5w+22)(w-3) = 0
\n" ); document.write( "the positive solution
\n" ); document.write( "w = 3 m is the original width
\n" ); document.write( "and
\n" ); document.write( "5(3) = 15 m is the length
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\n" ); document.write( ":
\n" ); document.write( "Check this
\n" ); document.write( "(15-3)(3+2) =
\n" ); document.write( "12*5 = 60\r
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