document.write( "Question 805860: one number is 6 more than 3 times another. Their product is 6 more than 3 times their sum. Find the numbers. Answer in the form of paired points with the lowest of the two integers first.
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Algebra.Com's Answer #485574 by ankor@dixie-net.com(22740)\"\" \"About 
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Two numbers, a & b
\n" ); document.write( "Write an equation for each statement:
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\n" ); document.write( "\"one number is 6 more than 3 times another.\"
\n" ); document.write( " a = 3b + 6
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\n" ); document.write( "\" Their product is 6 more than 3 times their sum.\"
\n" ); document.write( "ab = 3(a+b) + 6
\n" ); document.write( "ab = 3a + 3b + 6
\n" ); document.write( "Replace a with (3b+6)
\n" ); document.write( "b(3b+6) = 3(3b+6) + 3b + 6
\n" ); document.write( "3b^2 + 6b = 9b + 18 + 3b + 6
\n" ); document.write( "3b^2 + 6b = 12b + 24
\n" ); document.write( "Combine like terms on the left, to forma quadratic equation
\n" ); document.write( "3b^2 + 6b - 12b - 24 = 0
\n" ); document.write( "3b^2 - 6b - 24 = 0
\n" ); document.write( "simplify divide by 3
\n" ); document.write( "b^2 - 2b - 8 = 0
\n" ); document.write( "factors to
\n" ); document.write( "(b-4)(b+2) = 0
\n" ); document.write( "the positive solution is what we want here
\n" ); document.write( "b = 4
\n" ); document.write( "Find a
\n" ); document.write( "a = 3(4) + 6
\n" ); document.write( "a = 18
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\n" ); document.write( " Find the numbers. Answer in the form of paired points with the lowest of the two integers first.
\n" ); document.write( "4, 18; are the numbers
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\n" ); document.write( "Check this out using,\"ab = 3(a+b) + 6\"
\n" ); document.write( "18*4 = 3(18+4) + 6
\n" ); document.write( "72 = 3(22) + 6; confirms our solutions \n" ); document.write( "
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