document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=805747>Question 805747</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 1. in a triangle ABC angle=80 degree, if BD and CD are internal bisectors of angle B and angle C respectively, then the angle BDC is,\r<BR>\n" );
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document.write( "2. the side BC of the triangle ABC is produced to D. if angle ACD=112 degree and angle ABC=3/4 angle BAC, then the angle ABC is equal to </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #485505 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=485505\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 1. in a triangle ABC angle A=80 degree, if BD and CD are internal bisectors of angle B and angle C respectively, then the angle BDC is,\r<BR>\n" );
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document.write( "In triangle ABC angle A + Angle B +angle C = 180 Deg\r<BR>\n" );
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document.write( "Angle B +angle C = 180 Deg- angle A\r<BR>\n" );
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document.write( "=180-80=100 deg\r<BR>\n" );
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document.write( "In triangle BDC angle DBC + angle DCB + BDC = 180 deg\r<BR>\n" );
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document.write( "angle DBC = 1/2 angle B ( angular bisectors)<BR>\n" );
document.write( "angle DCB = 1/2 angle C\r<BR>\n" );
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document.write( "In triangle BDC 1/2 angle B +1/2 angle C + BDC = 180 deg\r<BR>\n" );
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document.write( "In triangle BDC 1/2 (angle B + angle C) + BDC = 180 deg\r<BR>\n" );
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document.write( "=1/2(100)+BDC= 180 deg\r<BR>\n" );
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document.write( "angle BDC = 180 -50\r<BR>\n" );
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document.write( "angle BDC= 130 deg\r<BR>\n" );
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document.write( "2. the side BC of the triangle ABC is produced to D. if angle ACD=112 degree and angle ABC=3/4 angle BAC, then the angle ABC is equal to\r<BR>\n" );
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document.write( "Let angle BAC = x<BR>\n" );
document.write( "angle ABC = 3x/4\r<BR>\n" );
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document.write( "x+ (3x/4) =112  ( The exterior angle is equal to the sum of two interior remote angles)\r<BR>\n" );
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document.write( "7x/4=112\r<BR>\n" );
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document.write( "7x=112*4<BR>\n" );
document.write( "x=16*4<BR>\n" );
document.write( "x=64 deg (BAC)\r<BR>\n" );
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document.write( "ABC = 3*64/4\r<BR>\n" );
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document.write( "ABC = 48 deg\r<BR>\n" );
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document.write( " </SPAN>\n" );
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