document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=805748>Question 805748</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A rectangular piece of land to be developed as a memorial park has an area of 48 m^2. The length of the lot is three times the width of the lot. A rectangular path whose width is x meters is to be constructed along the inner perimeter of the lot. The land contained within the path will be landscaped. The cost to construct the path is $2 per square meter and the cost to landscape the inner field is $3 per square meter. Express the total cost to develop this lot as a function of x, the width of the path.   </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #485451 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=485451\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> the area of plot = 48 m^2\r<BR>\n" );
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document.write( "ratio is 1/3 \r<BR>\n" );
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document.write( "Width = 1/4 * 48 = 12m<BR>\n" );
document.write( "length = 3times 12 = 36m\r<BR>\n" );
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document.write( "the width is x\r<BR>\n" );
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document.write( "Inner garden length = 36-2x<BR>\n" );
document.write( "inner garden width = 12-2x\r<BR>\n" );
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document.write( "Area of garden = (36-2x)(12-2x)<BR>\n" );
document.write( "Land scaping the garden $3 / m^2\r<BR>\n" );
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document.write( "Cost of landscaping = 3(36-2x)(12-2x)\r<BR>\n" );
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document.write( "Cost of pavement\r<BR>\n" );
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document.write( "area of pavement =  total area - area of inner garden\r<BR>\n" );
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document.write( "48- 3(36-2x)(12-2x)\r<BR>\n" );
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document.write( "cost of pavement = $2 /m^2\r<BR>\n" );
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document.write( "Cost of pavement = 2(48-3(36-2x)(12-2x))\r<BR>\n" );
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document.write( "Total cost\r<BR>\n" );
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document.write( "total cost C= cost of pavement + cost of landscaping inner garden\r<BR>\n" );
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document.write( "C= 2(48-3(36-2x)(12-2x)) + 3(36-2x)(12-2x)<BR>\n" );
document.write( "= 96-6(36-2x)(12-2x)) + 3(36-2x)(12-2x)\r<BR>\n" );
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document.write( "simplify if necessary\r<BR>\n" );
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