document.write( "Question 804988: I need help with writing a sigma notation of 1/2 + 3/4 + 5/6 + ... 99/100, but I keep on getting lost and going in circles. \n" ); document.write( "

Algebra.Com's Answer #485428 by AnlytcPhil(1806) $\"\"$ $\"About$

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1/2 + 3/4 + 5/6 + ... 99/100
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document.write( "The denominators are the even natural numbers 2,4,6,8, and the pattern is 2n for n = 1,...,50\r\n" );
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document.write( "The numerators are 1 less than the denominators, 1,3,5,7, so we subtract 1\r\n" );
document.write( "from that pattern 2n-1,\r\n" );
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document.write( "So the nth term is , where n goes from 1 to 50, so we can write that as\r\n" );
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document.write( "We can simplify, if desired:\r\n" );
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document.write( " =  = 1 - , so we write the summation as\r\n" );
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document.write( "and if we like we can distribute the summation as\r\n" );
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document.write( "Then the first summation is just the sum of 50 ones, which is just 50.\r\n" );
document.write( "So we can simplify it to\r\n" );
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document.write( "Edwin

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