document.write( "Question 805594: Jackie mows a strip of uniform width around her 25 m by 15 m rectangular lawn and leaves a patch of lawn that is 60% of the original area. What is the width of the strip? \n" ); document.write( "
Algebra.Com's Answer #485389 by josgarithmetic(39617)\"\" \"About 
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Original area, 25*15 square meters.
\n" ); document.write( "60% of original area, (0.6)(25)(15).
\n" ); document.write( "Let x = width of the strip around the unmowed area.\r
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\n" ); document.write( "\n" ); document.write( "One side of the unmowed rectangle is 25-2x meters.
\n" ); document.write( "The other side of the unmowed rectangle is 15-2x meters.\r
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\n" ); document.write( "\n" ); document.write( "Area of unmowed region is \"%2825-2x%29%2815-2x%29=%280.6%29%2825%29%2815%29\"
\n" ); document.write( "\"%2825-2x%29%2815-2x%29=225\"
\n" ); document.write( "\"375-30x-50x%2B4x%5E2=225\"
\n" ); document.write( "\"4x%5E2-80x%2B375-225=0\"
\n" ); document.write( "\"4x%5E2-80x%2B150=0\"
\n" ); document.write( "\"highlight%282x%5E2-40x%2B75=0%29\"\r
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\n" ); document.write( "\n" ); document.write( "If you do not feel like checking for factorability, use general solution:
\n" ); document.write( "\"x=%2840%2Bsqrt%281600-4%2A2%2A75%29%29%2F%282%2A2%29\"
\n" ); document.write( "\"x=%2840%2Bsqrt%281000%29%29%2F%282%2A2%29\"
\n" ); document.write( "\"x=%2840%2B100%29%2F4\"
\n" ); document.write( "\"x=10%2B25\"
\n" ); document.write( "\"highlight%28x=35%29\" meters
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