document.write( "Question 805613: Mr. Lavalle wants to mix 6 pounds of brand A with brand b to make a 10-pound mixture costing 11.50. How much can she afford to pay per pound for brand b if brand a costs 1.23 per pound? \n" ); document.write( "
Algebra.Com's Answer #485386 by josgarithmetic(39618)\"\" \"About 
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6 pounds Brand A, p dollars per pound.
\n" ); document.write( "4 pounds Brand B, 1.23 dollars per pound.
\n" ); document.write( "10 pounds mixture, 11.50 dollars per pound target price.\r
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\n" ); document.write( "\n" ); document.write( "\"%286p%2B4%2A%281.23%29%29%2F10=11.50\"\r
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\n" ); document.write( "\n" ); document.write( "The worded description may seem complicated if you are unaccustomed to price & cost descriptions, but that is the specific fractional equation fitting the description. Solve for p.
\n" ); document.write( " Mr. Lavalle does not want to pay more than price p for Brand A.
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