document.write( "Question 805197: How to divide this using synthetic division?
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document.write( "(X^3-5x^2-7x+25)/(x-5) \n" );
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Algebra.Com's Answer #485372 by coolcat!!!(1)![]() ![]() ![]() You can put this solution on YOUR website! You take (x-5) and take out the 5\r \n" ); document.write( "\n" ); document.write( "So: (x-5) => x=5\r \n" ); document.write( "\n" ); document.write( "You must then take only the coefficients of all the x's and the constant:\r \n" ); document.write( "\n" ); document.write( "X^3-5x^2-7x+25 => 1 -5 -7 25\r \n" ); document.write( "\n" ); document.write( "5 | 1 -5 - 7 25 \n" ); document.write( " | 5 0 -35 \n" ); document.write( " |________________ \n" ); document.write( " 1 0 -7 -10\r \n" ); document.write( "\n" ); document.write( "Explanation: you write the coefficients/constant in a line at the top, and then draw a vertical line on the left of the numbers, and -leaving some space- on horizontally under the numbers. \n" ); document.write( "Write what dividing by (the 5) on the left side of the vertical line. YOUR READY TO SYNTHETICALLY DIVIDE. \n" ); document.write( "That first number (the 1) is just brought down, so you write it under the horizontal line. \n" ); document.write( "Now, 1 times the number you are dividing (5) is 5. So place that between the numbers you initially had written and the horizontal line. Now, you must ADD that -5 and 5. So it is now 0. \n" ); document.write( "0 times the number you are dividing (5) is 0. Put the 0 under the next number in the line (-7). Now you ADD -7 and 0, which is -7. -7 times 5 is -35. Place -35 under the 25. \n" ); document.write( "Finally, the 25 plus -35 is -10.\r \n" ); document.write( "\n" ); document.write( "In conclusion, taking the numbers 1 0 -7 -10, \n" ); document.write( "the quotient is x^2-7 R: -10 \n" ); document.write( "The 1 is just the x^2 , the zero is 0x (so we don't write it) the -7 is the constant, and -10 is the remainder. \n" ); document.write( "We start with x^2 because the quotient has one less exponent at it's first x, than the initial equation that which we divided by (x-5) (because it was x^3.\r \n" ); document.write( "\n" ); document.write( "Hope this helped! Good luck! \n" ); document.write( " |